Matematika Sekolah Menengah Atas √144 - 4² = x-1 × 1 ÷ 1 × (√1) × (1/1) = yx-y=ztentukan berapa x, y, dan z tersebut.Bonus:1+3!​

clairenitzscheulv – March 20, 2023

√144 - 4² = x
-1 × 1 ÷ 1 × (√1) × (1/1) = y
x-y=z

tentukan berapa x, y, dan z tersebut.
Bonus:
1+3!​

Jawaban:

Δ Question Δ

√144 - 4² = x

-1 × 1 ÷ 1 × (√1) × (1/1) = y

x-y=z

Tentukan berapa x, y, dan z tersebut.

Bonus:

1+3!

Δ Answer Δ

x = -4

y = -1

z = -3

1 + 3! = 7

Δ Explanation Δ

1. √144 - 4² = x

x = √144 - 4²

x = 12 - ( 4 × 4 )

x = 12 - 16

x = -4

2. -1 × 1 ÷ 1 × (√1) × (1/1) = y

y = -1 × 1 ÷ 1 × (√1) × (1/1)

y = -1 × 1 ÷ 1 × 1 × 1

y = -1 ÷ 1 × 1 × 1

y = -1 × 1 × 1

y = -1 × 1

y = -1

3. x - y = z

z = -4 - ( -1 )

z = -3

4. = 1 + 3!

= 1 + ( 3 × 2 × 1 )

= 1 + ( 6 × 1 )

= 1 + 6

= 7

____________________________________

°°° Semoga Membantu °°°

Answer By : LatifaAzkaAzizah07

[answer.2.content]